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int *p(int, int) = add; 调用p(1,2)可得到结果3
int *p(int, int) = add;
p(1,2)
int (*p)(int, int) = &add; 调用(*p)(2,3)可得到结果5
int (*p)(int, int) = &add;
(*p)(2,3)
int (*p)(int) = add; 调用p(4)可得到结果4
int (*p)(int) = add;
p(4)
int (*p)(int, int) = add; 调用*p(1,3)可得到结果4
int (*p)(int, int) = add;
*p(1,3)