下面C++代码用于求1到N之间正整数中含有3的数的个数,比如123和32都是符合条件的数。代码如下:
int i,j; int cnt = 0, N; cout << "请输入正整数N:"; cin >> N; for (i = 1; (j=i) < N; i++) while (j != 0) if (j % 10 == 3) { cnt +=1; __________; } else __________; cout << cnt << " ";
1. continue 2. j /= 10
1. break 2. j /= 10
1. continue 2. j %= 10
1. break 2. j %= 10